Template:Needs Translation/
函数名
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Function: string llGetDate( )
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参数:
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返回值:返回UTC时区中当前日期的字符串,格式为“YYYY-MM-DD”。
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示例
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// Birthday surprise
default
{
state_entry()
{
llSetTimerEvent(0.1);
}
timer()
{
if(llGetDate() == "2009-02-15")
llSetText("HAPPY BIRTHDAY!", <0,1,0>, 1.0);
else
llSetText("A surprise is coming...", <0,1,0>, 1.0);
llSetTimerEvent(3600.0); // check every hour.
}
}
// Function to calculate the numeric day of year
integer dayOfYear(integer year, integer month, integer day)
{
return day + (month - 1) * 30 + (((month > 8) + month) / 2)
- ((1 + (((!(year % 4)) ^ (!(year % 100)) ^ (!(year % 400))) | (year <= 1582))) && (month > 2));
}
default
{
touch_end(integer count)
{
list dateComponents = llParseString2List(llGetDate(), ["-"], []);
integer year = (integer) llList2String(dateComponents, 0);
integer month = (integer) llList2String(dateComponents, 1);
integer day = (integer) llList2String(dateComponents, 2);
llSay(0, "The current day of the year is " + (string) dayOfYear(year, month, day));
}
}
// Function to calculate whether a current year is a leap year
integer is_leap_year( integer year )
{
if( year % 4 ) return FALSE; // Not a leap year under any circumstances
if( year <= 1582 ) return TRUE; // In the Julian calender before 24 February 1582, every fourth year was a leap year
if( !( year % 400 )) return TRUE; // A leap century is a leap year if divisible by 400
if( !( year % 100 )) return FALSE; // Any other century is not a leap year
return TRUE; // It is divisible by 4 and not a century and not Julian, therefore it is a leap year
}
之前的脚本对于《阿凡达时代》、SL的销售历史等来说是完全不必要的。下面是99%的SL应用程序所需要的全部内容。
该代码实际上对1901年至2099年的所有年份都有效,因为2000年是闰年。
if (year % 4) // TRUE if NOT a leap year
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