LlAngleBetween

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函数名
Function: float llAngleBetween( rotation a, rotation b );
参数：返回一个浮点数，它是旋转a和旋转b之间的弧度角。
•旋转a–开始旋转 •旋转b–结束旋转

注意事项
重要问题~Search JIRA for related Bugs

示例
default { touch_start(integer num_detected) { rotation currentRootRotation = llGetRootRotation(); float angle = llAngleBetween(ZERO_ROTATION, currentRootRotation); // PUBLIC_CHANNEL has the integer value 0 llSay(PUBLIC_CHANNEL, "llAngleBetween(ZERO_ROTATION, " + (string)currentRootRotation + ") = " + (string)angle); } }

相关函数
•llRotBetween•llRot2Angle

相关事件

== 参考 == float AngleBetween(rotation a, rotation b)//simple but turns out to not be very accurate. { return 2.0 * llAcos( llFabs(a.x * b.x + a.y * b.y + a.z * b.z + a.s * b.s) / llSqrt((a.x * a.x + a.y * a.y + a.z * a.z + a.s * a.s) * (b.x * b.x + b.y * b.y + b.z * b.z + b.s * b.s))); } float AngleBetween(rotation a, rotation b)//more complex implementation but more accurate, and reasonably fast. { rotation r = b / a; // calculate the rotation between the two arguments as quaternion float s2 = r.s * r.s; // square of the s-element float v2 = r.x * r.x + r.y * r.y + r.z * r.z; // sum of the squares of the v-elements if (s2 < v2) // compare the s-component to the v-component return 2.0 * llAcos(llSqrt(s2 / (s2 + v2))); // use arccos if the v-component is dominant if (v2) // make sure the v-component is non-zero return 2.0 * llAsin(llSqrt(v2 / (s2 + v2))); // use arcsin if the s-component is dominant return 0.0; // one or both arguments are scaled too small to be meaningful, or the values are the same, so return zero }//Written by Moon Metty & Miranda Umino. Minor optimizations by Strife Onizuka